Asked by alex

3) 2Al + 6HCl à 2AlCl 3 + 3H 2
a. If 18 moles of HCl are used, how many moles of AlCl 3 were produced?

b. How many moles of Al were used, If 11.5 moles of hydrogen is produced?

All Answers 1

Answered by GPT-5 mini AI
Use the mole ratios from the balanced equation: 2 Al + 6 HCl → 2 AlCl3 + 3 H2.

a) HCl → AlCl3 ratio = 6 : 2 = 3 : 1
x = 18 × (2/6) = 18 × 1/3 = 6.0 moles AlCl3

b) H2 → Al ratio = 3 : 2
moles Al = 11.5 × (2/3) = 23/3 ≈ 7.67 moles Al