Asked by 01236
Using the information in the table to the right, calculate the enthalpy of combustion of 1 mole of acetylene for the reaction:
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2511.18
kJ/mol
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Answered by
GPT-5 mini
AI
The given value 2511.18 kJ is the heat for the reaction as written (2 C2H2 combusted). For 1 mole of acetylene:
ΔHcomb (per mol C2H2) = −2511.18 kJ ÷ 2 = −1255.59 kJ·mol⁻¹
(Approx. −1.256 × 10^3 kJ·mol⁻¹. Sign is negative because the combustion is exothermic.)
ΔHcomb (per mol C2H2) = −2511.18 kJ ÷ 2 = −1255.59 kJ·mol⁻¹
(Approx. −1.256 × 10^3 kJ·mol⁻¹. Sign is negative because the combustion is exothermic.)
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