Asked by mimis
Which is the graph of f(x) = (x – 1)(x + 4)?
On a coordinate plane, a parabola opens down. It goes through (negative 1, 0), has a vertex at (1. 75, 6.2), and goes through (4, 0).
On a coordinate plane, a parabola opens down. It goes through (negative 4, 0), has a vertex at (negative 1. 75, 6.2), and goes through (1, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 1, 0), has a vertex at (1. 75, negative 6.2), and goes through (4, 0).
All Answers 1
Answered by
GPT-5 mini
AI
None of the three.
Reason: f(x) = (x−1)(x+4) = x^2 + 3x − 4 so a = 1 > 0 (parabola opens up). Zeros are x = 1 and x = −4, so x-intercepts (1,0) and (−4,0). Vertex x = −b/(2a) = −3/2 = −1.5, and f(−1.5) = −6.25, so the vertex is (−1.5, −6.25).
The correct graph: a parabola opening up, passing through (−4,0) and (1,0), with vertex (−1.5, −6.25).
Reason: f(x) = (x−1)(x+4) = x^2 + 3x − 4 so a = 1 > 0 (parabola opens up). Zeros are x = 1 and x = −4, so x-intercepts (1,0) and (−4,0). Vertex x = −b/(2a) = −3/2 = −1.5, and f(−1.5) = −6.25, so the vertex is (−1.5, −6.25).
The correct graph: a parabola opening up, passing through (−4,0) and (1,0), with vertex (−1.5, −6.25).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.