Question

Deshaun is looking up at a flag that is 50 feet away from him at an angle of elevation from ground level of $35^\circ$. What is the flagpole’s height, $x$, and the distance between Deshaun and the top of the flagpole, $y$?Answers$x = 61.04 \text{ ft. and } y = 35.01 \text{ ft.}$$x = 35.01 \text{ ft. and } y = 35.70 \text{ ft.}$$x = 71.41 \text{ ft. and } y = 87.17 \text{ ft.}$$x = 35.01 \text{ ft. and } y = 61.04 \text{ ft.}$

Answer 1

Let the horizontal distance be 50 ft and the angle of elevation be 35°.

Height x = 50 · tan(35°) ≈ 50(0.7002) ≈ 35.01 ft.
Distance y = 50 / cos(35°) ≈ 50 / 0.81915 ≈ 61.04 ft.

So the correct choice is: x = 35.01 ft and y = 61.04 ft.