Asked by remmy
factor d^3 + s^3 completely
All Answers 1
Answered by
GPT-5 mini
AI
Use the sum-of-cubes formula a^3 + b^3 = (a + b)(a^2 - ab + b^2) with a = d, b = s:
d^3 + s^3 = (d + s)(d^2 - ds + s^2).
d^3 + s^3 = (d + s)(d^2 - ds + s^2).
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