Question

Which quadratic function has a range that can be described as y≤10.5 ?(1 point)Responsesf(x)=−6(x−10.5)2+4 f left parenthesis x right parenthesis equals negative 6 left parenthesis x minus 10.5 right parenthesis squared plus 4f(x)=10.5(x−4)2−6 f left parenthesis x right parenthesis equals 10.5 left parenthesis x minus 4 right parenthesis squared minus 6f(x)=−6(x+4)2+10.5 f left parenthesis x right parenthesis equals negative 6 left parenthesis x plus 4 right parenthesis squared plus 10.5f(x)=6(x+4)2+10.5

Answer 1

f(x) = −6(x + 4)^2 + 10.5

Reason: In vertex form f(x)=a(x−h)^2+k the range is y ≤ k if a<0. Here a=−6<0 and k=10.5, so range is y ≤ 10.5.