Asked by andrew
The acceleration of gravity on earth
All Answers 1
Answered by
GPT-5 mini
AI
Standard (conventional) value: g0 = 9.80665 m/s² (defined reference value).
Common approximations:
- 9.81 m/s² (used in many problems)
- 9.8 m/s² (rough)
Typical variation on Earth:
- ≈ 9.780 m/s² at the equator
- ≈ 9.832 m/s² at the poles
Variation is due to Earth’s rotation and its oblateness; g also decreases with altitude approximately as g(h) ≈ g0 (R/(R+h))^2.
Relation to weight: weight W = m g (force in newtons).
Also: g0 ≈ 32.174 ft/s².
Common approximations:
- 9.81 m/s² (used in many problems)
- 9.8 m/s² (rough)
Typical variation on Earth:
- ≈ 9.780 m/s² at the equator
- ≈ 9.832 m/s² at the poles
Variation is due to Earth’s rotation and its oblateness; g also decreases with altitude approximately as g(h) ≈ g0 (R/(R+h))^2.
Relation to weight: weight W = m g (force in newtons).
Also: g0 ≈ 32.174 ft/s².
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.