Question

Which equation is represented by the graph below?

On a coordinate plane, a curve starts at (0, negative 3) in quadrant 4 and then increases into quadrant 1 and approaches y = 3.
y = e Superscript x
y = e Superscript x Baseline minus 1
y = l n x
y = l n x minus 1

Answer 1

y = ln x

Reason: The graph shows a curve with a vertical asymptote at x = 0 (very negative y-values near x = 0+) and then rising slowly into quadrant I, which is the characteristic shape of a natural logarithm. Exponential functions (e^x and e^x − 1) do not have a vertical asymptote at x = 0, and ln x − 1 is the same shape shifted down by 1.