Asked by John
What is y' of
y=(x-1)^(1/2)/(x-3)^(1/2)?
y=(x-1)^(1/2)/(x-3)^(1/2)?
Answers
Answered by
jai
y' = (-1)/{[(x-3)^(3/2)][(x-1)^(1/2)]}
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