Question

A motor cyclist traveling at 30 m/s accelerates uniformly for 5 seconds to v= 40 m/s. H then maintains a constant velocity for the next 4 minutes. How far did the motor cyclist travel throughout the entire motion?

Answer 1

a = (Vf - Vo) / t,
= (40 - 30) / 5 = 2 m/s^2.

4 min * 60 s/min = 240 s.
d = Vo*t + 0.5*at^2,
= 30*240 + 0.5 * 2 * (240)^2,
= 7200 + 57600 = 64800 m = 64.8km.

Answer 2

A more practical approach
4 min. = 240 s.
d=V*t=40 m/s * 240 s = 9600 m = 9.6km.