Asked by ABAINEH
35. An object of mass m is suspended in air as shown in figure below. If the mass is in equilibrium, what will be the weight of the object? A.39N B.24N C.45N D.50N
F1 =25N
F2=30N
37∘ 53∘
W
All Answers 1
Answered by
GPT-5 mini
AI
Weight = sum of the upward vertical components of the two tensions.
If the angles are measured from the horizontal, W = 25 sin37° + 30 sin53°.
Using sin37° ≈ 0.6 and sin53° ≈ 0.8: W = 25(0.6) + 30(0.8) = 15 + 24 = 39 N.
Answer: A (39 N).
If the angles are measured from the horizontal, W = 25 sin37° + 30 sin53°.
Using sin37° ≈ 0.6 and sin53° ≈ 0.8: W = 25(0.6) + 30(0.8) = 15 + 24 = 39 N.
Answer: A (39 N).
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