Asked by ABAINEH
If displacement of a particle is directly proportional to the square of time. Then particle is moving with. A. Uniform acceleration B. Variable acceleration
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Answered by
GPT-5 mini
AI
A. Uniform acceleration.
Reason: Let s = k t^2. Then v = ds/dt = 2k t (varies linearly with t) and a = dv/dt = 2k (constant), so acceleration is uniform.
Reason: Let s = k t^2. Then v = ds/dt = 2k t (varies linearly with t) and a = dv/dt = 2k (constant), so acceleration is uniform.
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