Asked by Bob
g(x)=\sqrt{x+3}
All Answers 1
Answered by
GPT-5 mini
AI
Here are key properties of g(x) = √(x + 3) = (x + 3)^{1/2}:
- Domain: x + 3 ≥ 0 ⇒ x ≥ −3.
- Range: y ≥ 0.
- Intercepts: g(−3) = 0 (x-intercept); g(0) = √3 (y-intercept).
- Monotonicity: strictly increasing on its domain.
- Continuity/differentiability: continuous for x ≥ −3; differentiable for x > −3. Not differentiable at x = −3 (vertical tangent / infinite slope).
- Derivative: g'(x) = 1 / (2√(x + 3)) for x > −3.
- Second derivative: g''(x) = −1 / (4(x + 3)^{3/2}) for x > −3 (concave down).
- Integral: ∫√(x + 3) dx = (2/3)(x + 3)^{3/2} + C.
- Inverse function: g^{-1}(y) = y^2 − 3 with domain y ≥ 0.
- Graph: the basic √x curve shifted left by 3 units; starts at point (−3, 0) and increases slowly to +∞ as x → +∞.
If you want a plot, numerical values, or composition/inverse verification, tell me what format you prefer.
- Domain: x + 3 ≥ 0 ⇒ x ≥ −3.
- Range: y ≥ 0.
- Intercepts: g(−3) = 0 (x-intercept); g(0) = √3 (y-intercept).
- Monotonicity: strictly increasing on its domain.
- Continuity/differentiability: continuous for x ≥ −3; differentiable for x > −3. Not differentiable at x = −3 (vertical tangent / infinite slope).
- Derivative: g'(x) = 1 / (2√(x + 3)) for x > −3.
- Second derivative: g''(x) = −1 / (4(x + 3)^{3/2}) for x > −3 (concave down).
- Integral: ∫√(x + 3) dx = (2/3)(x + 3)^{3/2} + C.
- Inverse function: g^{-1}(y) = y^2 − 3 with domain y ≥ 0.
- Graph: the basic √x curve shifted left by 3 units; starts at point (−3, 0) and increases slowly to +∞ as x → +∞.
If you want a plot, numerical values, or composition/inverse verification, tell me what format you prefer.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.