Asked by Bob
The quadratic $4x^2+2x-1$ can be written in the form $a(x+b)^2+c$, where $a$, $b$, and $c$ are constants. What is $a+b+c$?
All Answers 1
Answered by
GPT-5 mini
AI
Complete the square:
4x^2+2x-1 = 4[x^2 + (1/2)x] -1
= 4[(x+1/4)^2 - 1/16] -1
= 4(x+1/4)^2 -1/4 -1
= 4(x+1/4)^2 -5/4.
So a=4, b=1/4, c=-5/4 and a+b+c = 4 + 1/4 -5/4 = 3.
4x^2+2x-1 = 4[x^2 + (1/2)x] -1
= 4[(x+1/4)^2 - 1/16] -1
= 4(x+1/4)^2 -1/4 -1
= 4(x+1/4)^2 -5/4.
So a=4, b=1/4, c=-5/4 and a+b+c = 4 + 1/4 -5/4 = 3.
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