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3 moles of N2 how many of NH3 would be produced
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Assuming the Haber reaction N2 + 3 H2 → 2 NH3 and that H2 is in excess, 1 mol N2 produces 2 mol NH3. So 3 mol N2 → 3 × 2 = 6 mol NH3.
(If you want mass: molar mass NH3 ≈ 17.03 g/mol, so 6 mol ≈ 102.2 g NH3.)
(If you want mass: molar mass NH3 ≈ 17.03 g/mol, so 6 mol ≈ 102.2 g NH3.)
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