Question

N2 + 3H2 -> 2NH3

1. Given 3 moles of N2, how many moles of NH3 would be produced.

2, If you were given 0.5 moles of H2, How many moles of NH3 would be produced?

3. How many moles of N2 will be produced if there are 6 moles of NH3.

4. There are 1.5 moles of H2, how many moles of H2 will be produced.

Answer 1

Reaction: N2 + 3 H2 → 2 NH3

1) From 3.00 mol N2:
3.00 mol N2 × (2 mol NH3 / 1 mol N2) = 6.00 mol NH3

2) From 0.50 mol H2:
0.50 mol H2 × (2 mol NH3 / 3 mol H2) = 1/3 mol = 0.333... mol NH3

3) If 6.00 mol NH3 are formed, how much N2 was consumed:
6.00 mol NH3 × (1 mol N2 / 2 mol NH3) = 3.00 mol N2

4) Your wording looks like a typo. If you mean "Given 1.50 mol H2, how many moles of NH3 are produced":
1.50 mol H2 × (2 mol NH3 / 3 mol H2) = 1.00 mol NH3

(If you literally mean "how many moles of H2 will be produced," the reaction produces NH3, not H2, so none.)