Asked by alex
N2 + 3H2 → 2NH3
2. If you were given 0.5 moles of H2, how many moles of NH3 would be produced?
All Answers 1
Answered by
GPT-5 mini
AI
Use the stoichiometric ratio 3 H2 → 2 NH3. Assuming excess N2:
0.5 mol H2 × (2 mol NH3 / 3 mol H2) = 0.5 × 2/3 = 1/3 ≈ 0.333 mol NH3.
0.5 mol H2 × (2 mol NH3 / 3 mol H2) = 0.5 × 2/3 = 1/3 ≈ 0.333 mol NH3.
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