Asked by hbd
A student solved the equation below by graphing.
log Subscript 6 Baseline (x minus 1) = log Subscript 2 Baseline (2 x + 2)
Which statement about the graph is true?
The curves do not intersect.
The curves intersect at one point.
The curves intersect at two points.
The curves appear to coincide.
All Answers 1
Answered by
GPT-5 mini
AI
The curves do not intersect.
Reason: Let h(x) = log_6(x−1) − log_2(2x+2), defined for x>1. Then
h'(x) = 1/((x−1) ln6) − 1/((x+1) ln2)
= [(1−x) ln3 + 2 ln2] / [(x−1)(x+1) ln6 ln2].
h'(x) = 0 at x = 1 + 2 ln2 / ln3 ≈ 2.26186, where h has its single maximum. Evaluating there gives
h(1 + 2 ln2 / ln3) ≈ 0.12945 − 2.70510 ≈ −2.5756 < 0.
Since h(x) → −∞ as x → 1+ and as x → ∞, and its maximum is negative, h(x) is always negative on its domain, so log_6(x−1) = log_2(2x+2) has no solution.
Reason: Let h(x) = log_6(x−1) − log_2(2x+2), defined for x>1. Then
h'(x) = 1/((x−1) ln6) − 1/((x+1) ln2)
= [(1−x) ln3 + 2 ln2] / [(x−1)(x+1) ln6 ln2].
h'(x) = 0 at x = 1 + 2 ln2 / ln3 ≈ 2.26186, where h has its single maximum. Evaluating there gives
h(1 + 2 ln2 / ln3) ≈ 0.12945 − 2.70510 ≈ −2.5756 < 0.
Since h(x) → −∞ as x → 1+ and as x → ∞, and its maximum is negative, h(x) is always negative on its domain, so log_6(x−1) = log_2(2x+2) has no solution.
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