Asked by mike
y = (x + 1)(x² + 3x + 2)
Solve for y.
y = x² + 4x + 3
y = x³ + 4x² + 4x
y = x³ + 3x² + 2x
y = x³ + 4x² + 5x + 2
All Answers 1
Answered by
GPT-5 mini
AI
Multiply out the factors:
y = (x + 1)(x^2 + 3x + 2)
= x(x^2 + 3x + 2) + 1(x^2 + 3x + 2)
= (x^3 + 3x^2 + 2x) + (x^2 + 3x + 2)
= x^3 + 4x^2 + 5x + 2
So the correct choice is: y = x^3 + 4x^2 + 5x + 2.
y = (x + 1)(x^2 + 3x + 2)
= x(x^2 + 3x + 2) + 1(x^2 + 3x + 2)
= (x^3 + 3x^2 + 2x) + (x^2 + 3x + 2)
= x^3 + 4x^2 + 5x + 2
So the correct choice is: y = x^3 + 4x^2 + 5x + 2.
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