Question

Which equation has x = –6 as the solution?
log Subscript x Baseline 36 = 2
log Subscript 3 Baseline (2 x minus 9) = 3
log Subscript 3 Baseline 216 = x
log Subscript 3 Baseline (negative 2 x minus 3) = 2

Answer 1

log_3(−2x − 3) = 2.

Solve: −2x − 3 = 3^2 = 9 → −2x = 12 → x = −6.
(Check: argument = −2(−6) − 3 = 9 > 0, so it's valid.)

(For reference: log_x 36 = 2 gives x^2 = 36 so algebraically x = ±6, but a log base must be positive ≠1, so x = −6 is not allowed there.)