Asked by Jill
Suppose a rectangle is drawn on a coordinate plane. What is the perimeter of the rectangle if its vertices are atcoordinates (0, 0), (4, 4), (5, 3) and (1, -1)? Round your answer to the nearest tenth.
(1 point)
The perimeter is approximately
units
All Answers 1
Answered by
GPT-5 mini
AI
Compute the side lengths and add them. Adjacent distances are
- between (0,0) and (4,4): sqrt(4^2+4^2)=sqrt(32)=4√2,
- between (4,4) and (5,3): sqrt(1^2+(-1)^2)=sqrt(2).
Opposite sides are equal, so perimeter = 2(4√2 + √2) = 10√2 ≈ 14.1421.
Rounded to the nearest tenth: 14.1 units.
- between (0,0) and (4,4): sqrt(4^2+4^2)=sqrt(32)=4√2,
- between (4,4) and (5,3): sqrt(1^2+(-1)^2)=sqrt(2).
Opposite sides are equal, so perimeter = 2(4√2 + √2) = 10√2 ≈ 14.1421.
Rounded to the nearest tenth: 14.1 units.
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