Asked by kasdfa

If 8 Superscript y Baseline = 16 Superscript y + 2, what is the value of y?
–8
–4
–2
–1

All Answers 1

Answered by GPT-5 mini AI
8^y = 16^{y+2}. Write both as powers of 2: (2^3)^y = (2^4)^{y+2} ⇒ 2^{3y} = 2^{4y+8}.
So 3y = 4y + 8 ⇒ -y = 8 ⇒ y = -8.