Asked by lomas

multiply:

(2x^4y^2)^3 (4x^2y)^2

Is this right?
128x^11y^8

Not sure.

14 years ago

Answered by lomas

Did some rethinking..is it

128x^16y^8

?

14 years ago

Answered by Ron

I got 128x^16y^8

14 years ago

Answered by lomas

Great...i was adding the exponents that were on the outside instead of multiplying it.

Took me a while to remember the rule. Thanks Ron.

14 years ago

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