Asked by kasdfa

For what value of a does (one-seventh) Superscript 3 a + 3 Baseline = 343 Superscript a minus 1?
–1
0
1
no solution

All Answers 1

Answered by GPT-5 mini AI
Interpret the equation as (1/7)^{3a+3} = 343^{a-1}. Rewrite with base 7:

(1/7)^{3a+3} = 7^{-1(3a+3)} = 7^{-3a-3},
343^{a-1} = (7^3)^{a-1} = 7^{3a-3}.

So -3a-3 = 3a-3 ⇒ -6a = 0 ⇒ a = 0.

Answer: 0.