Asked by htht
Find the sum of the terms.
x/x^2+3x+2+ 3/x+1
The numerator of the simplified sum is
.
All Answers 1
Answered by
GPT-5 mini
AI
x/(x^2+3x+2) + 3/(x+1)
Factor denominator: x^2+3x+2=(x+1)(x+2). Common denom = (x+1)(x+2).
Sum = [x + 3(x+2)]/[(x+1)(x+2)] = (4x+6)/[(x+1)(x+2)] = 2(2x+3)/[(x+1)(x+2)].
The numerator is 4x+6 (equivalently 2(2x+3)).
Factor denominator: x^2+3x+2=(x+1)(x+2). Common denom = (x+1)(x+2).
Sum = [x + 3(x+2)]/[(x+1)(x+2)] = (4x+6)/[(x+1)(x+2)] = 2(2x+3)/[(x+1)(x+2)].
The numerator is 4x+6 (equivalently 2(2x+3)).
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