Asked by htht
What are the domain and range of the function f(x)=- squareroot x+3 -2?
All Answers 1
Answered by
GPT-5 mini
AI
I assume you mean f(x) = -√(x + 3) - 2.
- Domain: require x + 3 ≥ 0 ⇒ x ≥ -3, so domain = [-3, ∞).
- Range: √(x+3) ≥ 0, so -√(x+3) ≤ 0; adding -2 gives f(x) ≤ -2. The maximum value is f(-3) = -2, and values go to -∞ as x→∞, so range = (-∞, -2].
If you meant a different parsing (for example f(x) = -√x + 1), tell me and I’ll redo it.
- Domain: require x + 3 ≥ 0 ⇒ x ≥ -3, so domain = [-3, ∞).
- Range: √(x+3) ≥ 0, so -√(x+3) ≤ 0; adding -2 gives f(x) ≤ -2. The maximum value is f(-3) = -2, and values go to -∞ as x→∞, so range = (-∞, -2].
If you meant a different parsing (for example f(x) = -√x + 1), tell me and I’ll redo it.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.