Asked by v
While hiking, Julia kicked a small rock off a ledge that was meters above a crevasse. The graph of the function is shown below. Use the graph to determine when the rock will hit the bottom of the crevasse, 2 meters below ground level. Round your answer to the nearest tenth of a second.
(1 point)
The rock will hit the bottom of the crevasse in
seconds.
Question 2
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Use the image to answer the question.
A parabola is graphed on a coordinate plane. The x-axis ranges from negative 2 to 10 in increments of 1. The y-axis ranges from negative 8 to 3 in increments of 1.
A sports analyst graphed the trajectory of a soccer ball that was kicked by a goalkeeper. In the graph, x is the ball’s distance from the goalpost, and y is the height of the ball in meters. What is the maximum height that the kicked ball reached?
(1 point)
The maximum height of the kicked ball was
meters.
All Answers 1
Answered by
GPT-5 mini
AI
I can’t see the graphs you mention. Could you either upload the images or type the function/equation(s) shown on the graphs?
Meanwhile, here are the steps to get the answers once the graph or equation is available:
1) Rock hitting the crevasse (height = −2 m)
- If you have a formula h(t) (height vs time), set h(t) = −2 and solve for t. Choose the positive time value (or the larger positive root if it passes −2 twice). Round that t to the nearest tenth of a second.
- If you only have the graph, find the t-coordinate(s) where the graph crosses the horizontal line y = −2; pick the physically relevant positive time and round to the nearest tenth.
2) Maximum height of the soccer ball
- If the ball’s trajectory is given by a quadratic y = ax^2 + bx + c, compute the vertex y-value: x_vertex = −b/(2a), then y_max = a(x_vertex)^2 + b(x_vertex) + c.
- If you only have the graph, read off the y-coordinate of the parabola’s highest point (the vertex). That y-value is the maximum height (in meters).
Send the graph or the equation and I’ll compute the numeric answers and round them as requested.
Meanwhile, here are the steps to get the answers once the graph or equation is available:
1) Rock hitting the crevasse (height = −2 m)
- If you have a formula h(t) (height vs time), set h(t) = −2 and solve for t. Choose the positive time value (or the larger positive root if it passes −2 twice). Round that t to the nearest tenth of a second.
- If you only have the graph, find the t-coordinate(s) where the graph crosses the horizontal line y = −2; pick the physically relevant positive time and round to the nearest tenth.
2) Maximum height of the soccer ball
- If the ball’s trajectory is given by a quadratic y = ax^2 + bx + c, compute the vertex y-value: x_vertex = −b/(2a), then y_max = a(x_vertex)^2 + b(x_vertex) + c.
- If you only have the graph, read off the y-coordinate of the parabola’s highest point (the vertex). That y-value is the maximum height (in meters).
Send the graph or the equation and I’ll compute the numeric answers and round them as requested.
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