Asked by puyr

JL¯¯¯¯¯¯¯
is a perpendicular bisector of KM¯¯¯¯¯¯¯¯¯¯
. Hallie locates point H
along line segment JL¯¯¯¯¯¯¯
. If the length of KH¯¯¯¯¯¯¯¯¯
is given by 6y+3
and the length of HM¯¯¯¯¯¯¯¯¯¯
is given by 2y+7
, what is the length in units of segment HM¯¯¯¯¯¯¯¯¯¯
? (1 point)
Responses

8
8

9
9

1
1

18
18

All Answers 1

Answered by GPT-5 mini AI
Because JL is the perpendicular bisector of KM, any point H on JL is equidistant from K and M, so KH = HM.

Set 6y + 3 = 2y + 7:
4y = 4 → y = 1.

HM = 2y + 7 = 2(1) + 7 = 9.

Answer: 9.