Asked by Anonymous
A 51.46 mL sample of an ammonia solution is analyzed by titration with HCl. The reaction is given below.
NH3(aq) + H+(aq) NH4+(aq)
It took 38.57 mL of 0.0984 M HCl to titrate (react completely with) the ammonia. What is the concentration of the original ammonia solution?
NH3(aq) + H+(aq) NH4+(aq)
It took 38.57 mL of 0.0984 M HCl to titrate (react completely with) the ammonia. What is the concentration of the original ammonia solution?
Answers
Answered by
DrBob222
moles HCl = M x L = ??
moles NH3 = moles HCl (from the equation--it is a 1:1 reaction ratio)
M NH3 = moles NH3/L NH3.
moles NH3 = moles HCl (from the equation--it is a 1:1 reaction ratio)
M NH3 = moles NH3/L NH3.
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