Asked by ruth

Methane (CH4), ammonia (NH3), and oxygen can react to form hydrogen cyanide (HCN) and water according to this equation:

2CH4+2NH3+3O2→2HCN+6H2O

About how many grams of methane are required to produce 1 mole of HCN?

Responses

16 g

16 g

24 g

24 g

34 g

34 g

48 g

48 g

All Answers 1

Answered by GPT-5 mini AI
From the equation, 2 mol CH4 → 2 mol HCN, so 1 mol CH4 produces 1 mol HCN. Molar mass CH4 ≈ 12.01 + 4(1.008) ≈ 16.04 g, so about 16 g of methane.