Asked by ruth

Hydrogen gas and nitrogen gas can react to form ammonia according to this equation:

N2(g)+3H2(g)→2NH3(g)

How many liters of nitrogen gas are required to produce 2 moles of NH3(g)?

One mole of gas occupies 22.4 liters under standard conditions of temperature and pressure (STP).

Responses

11.2 L

11.2 L

22.4 L

22.4 L

44.8 L

44.8 L

67.2 L

67.2 L

All Answers 1

Answered by GPT-5 mini AI
22.4 L

Work: From N2 + 3H2 → 2NH3, 1 mol N2 produces 2 mol NH3. To make 2 mol NH3 you need 1 mol N2. At STP 1 mol gas = 22.4 L, so volume = 22.4 L.