Question

Given that f(x)=x−1
and g(x)=x2+3x−6
, find (f+g)(2)
.(1 point)
(f+g)(2)=

Remaining Attempts :

Answer 1

(f+g)(x) = f(x)+g(x) = (x−1)+(x^2+3x−6) = x^2+4x−7.
Then (f+g)(2) = 2^2 + 4(2) − 7 = 4 + 8 − 7 = 5.