Question

3X+4Y<12 the inequality sign also has a line underneath

Answer 1

oh, so it's "less than or equal to"
you have to change this into y = mx + b (slope-intercept form), alright to do this, transpose 3x to the right side of equation, and divide everything by 4 to get y,,
let me see your answer for this first. :)

Answer 2

4y+3x=12 it also says that i have to graph it. If I graph the x on 4 and the y on 3 would that be correct if not where do i have to graph the coordinates at?

Answer 3

oh sorry it is supposed to be 3x+4y=12? right so where do i graph these at. what are the coordinates?

Answer 4

no. don't look for points yet. first, convert the given equation into slope-intercept form, y=mx+b,,
alright i'll help you in this one:
3x+4y<12
now to solve for y, transpose 3x to the right side of equation, but the sign becomes the opposite (positive 3x becomes -3x:
4y < 12 - 3x
then to get y alone, divide all terms by 4:
y < 12/4 - (3/4)x
y < 3 - (3/4)x or
y < (-3/4)x + 3 *slope intercept form*

now, find the x-intercept and y-intercept,, first treat this as
y = (-3/4)x + 3
to get x-intercept: let y = 0 and solve for x
to get y-intercept: let x = 0 and solve for y

let me see your work. :)

Answer 5

can you just give me the answer please

Answer 6

No, we do not give the answers here. That will not help you learn this.

Answer 7

3x + 4y =< 12.
We graph the ineguality by graphing the
boundary line:

Graph: 3x + 4y = 12.
Let x = 0:
3*0 + 4y = 12,
4y = 12,
y = 12 / 4 = 3,
P1(0 , 3).

Let y = 0:
3x + 4*0 = 12,
3x = 12,
x = 12 / 3 = 4.
P2(4 , 0).

Use these points for graphing:
P1(0 , 3) , P2(4 , 0).

Since your inequality includes an = sign, all points on the line should
satisfy the inequality. The < sign means that all points below the line
should satisfy the inequality also.