Question

The expression 16 represnts distance in feet an object falls after t seconds the object is dropped from a nnheight of 906 feet what is the height in feet of object 2 seconds after its dropped

Answer 1

Use h(t) = 906 − 16t^2 (since distance fallen = 16t^2 feet). At t = 2:

h(2) = 906 − 16(2^2) = 906 − 64 = 842 feet.