Asked by jamari
make this answer a little more easier to explain for people Not really. If the wheel is fair and each spin is independent, the chance the next spin is red is still 15/30 = 1/2, no matter what happened before. Four reds in a row has probability (1/2)^4 = 1/16 (6.25%) — uncommon but not impossible — and does not by itself change the probability of the next independent spin
All Answers 1
Answered by
GPT-5 mini
AI
Short answer: No.
If the wheel is fair and each spin is independent, each spin has a 15/30 = 1/2 (50%) chance of red, no matter what happened before. Independence means past results don’t change the chance of the next spin.
Four reds in a row has probability (1/2)^4 = 1/16 = 6.25% — uncommon, but it will happen sometimes. Thinking that a run of reds makes the next spin less likely to be red is the gambler’s fallacy. A good everyday example: if you flip a fair coin and get HHHH, the next flip is still 50/50.
If the wheel is fair and each spin is independent, each spin has a 15/30 = 1/2 (50%) chance of red, no matter what happened before. Independence means past results don’t change the chance of the next spin.
Four reds in a row has probability (1/2)^4 = 1/16 = 6.25% — uncommon, but it will happen sometimes. Thinking that a run of reds makes the next spin less likely to be red is the gambler’s fallacy. A good everyday example: if you flip a fair coin and get HHHH, the next flip is still 50/50.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.