Asked by tt
HOW DOES THE MASS OF AN OBJECT EFFECT THE SPEED THE OBJECT MOVES AT?
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Answered by
GPT-5 mini
AI
Short answer: Mass does not directly set an object's speed, but it strongly affects how the object’s speed changes when forces or energies are applied.
Key points
- Newton’s 2nd law: a = F/m. For a given applied force F, a larger mass m gives a smaller acceleration a, so after the same time the heavier object will be moving more slowly. Example: push with 10 N for 5 s:
- m = 2 kg → a = 5 m/s² → v = 25 m/s
- m = 10 kg → a = 1 m/s² → v = 5 m/s
- Gravity near Earth: gravitational acceleration g ≈ 9.8 m/s² is (nearly) the same for all masses. In a vacuum, a heavy rock and a light feather fall with the same acceleration and reach the same speeds. In air, drag changes this (see next point).
- Air resistance and terminal velocity: with drag, heavier objects usually reach higher terminal speeds because weight (mg) must be balanced by drag. For quadratic drag the terminal speed v_t satisfies mg ≈ (1/2)ρC_dA v_t^2, so v_t ∝ sqrt(m). That’s why a heavy skydiver falls faster than a light one with the same shape.
- Energy and momentum relations:
- For a given kinetic energy KE, v = sqrt(2KE/m) — more mass means lower speed for the same energy.
- For a given momentum p, v = p/m — more mass means lower speed for the same momentum.
Summary: Mass determines how an object responds to forces (heavier → less acceleration for the same force) and affects terminal speeds and energy–speed relationships, but mass alone doesn’t fix an object’s speed — the forces and energies acting on it do.
Key points
- Newton’s 2nd law: a = F/m. For a given applied force F, a larger mass m gives a smaller acceleration a, so after the same time the heavier object will be moving more slowly. Example: push with 10 N for 5 s:
- m = 2 kg → a = 5 m/s² → v = 25 m/s
- m = 10 kg → a = 1 m/s² → v = 5 m/s
- Gravity near Earth: gravitational acceleration g ≈ 9.8 m/s² is (nearly) the same for all masses. In a vacuum, a heavy rock and a light feather fall with the same acceleration and reach the same speeds. In air, drag changes this (see next point).
- Air resistance and terminal velocity: with drag, heavier objects usually reach higher terminal speeds because weight (mg) must be balanced by drag. For quadratic drag the terminal speed v_t satisfies mg ≈ (1/2)ρC_dA v_t^2, so v_t ∝ sqrt(m). That’s why a heavy skydiver falls faster than a light one with the same shape.
- Energy and momentum relations:
- For a given kinetic energy KE, v = sqrt(2KE/m) — more mass means lower speed for the same energy.
- For a given momentum p, v = p/m — more mass means lower speed for the same momentum.
Summary: Mass determines how an object responds to forces (heavier → less acceleration for the same force) and affects terminal speeds and energy–speed relationships, but mass alone doesn’t fix an object’s speed — the forces and energies acting on it do.
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