Asked by c
answer in the simplest way and like a teen would understand
A manufacturer claims that their battery for a particular cell phone model lasts 10 hours.
However, consumers complained that the batteries lasted less than 10 hours.
The manufacturer randomly sampled 24 batteries and found that the mean battery life of the sample was 9.4 hours with astandard deviation of 0.25 hours.
Based on the data given, is there evidence that the manufacturer’s claim is false?
Justify your answer.
also actually explain the math because you sometimes put random slashes and confuse me
All Answers 1
Answered by
GPT-5 mini
AI
Short answer: Yes. There is very strong evidence the batteries last less than 10 hours.
Step-by-step (simple math, no weird slashes):
1) Set up the test
- Claim says mean life mu = 10 hours.
- Consumers say it’s less, so we test:
- Null hypothesis H0: mu = 10
- Alternative hypothesis Ha: mu < 10 (one-sided)
2) Use a t-test (because the population standard deviation is unknown and sample size is 24)
- Sample size n = 24
- Sample mean x̄ = 9.4 hours
- Sample standard deviation s = 0.25 hours
- Degrees of freedom = n − 1 = 23
3) Compute the standard error (how much the sample mean typically varies)
- sqrt(24) ≈ 4.899
- standard error = s divided by sqrt(n) = 0.25 / 4.899 ≈ 0.05103
4) Compute the t-statistic
- t = (x̄ − 10) divided by standard error
- That is t = (9.4 − 10) / 0.05103 = −0.6 / 0.05103 ≈ −11.76
5) Decide using t and p-value
- With 23 degrees of freedom, a t of −11.76 is extremely far into the left tail.
- The p-value is basically 0 (much smaller than 0.01).
- Even using a common cutoff like 0.05, this t is way beyond the critical value (about −1.714), so we reject H0.
6) Conclusion in plain teen talk
- The data show the average battery life is significantly less than 10 hours. The manufacturer’s 10-hour claim is not supported by this sample — it’s very likely false.
Step-by-step (simple math, no weird slashes):
1) Set up the test
- Claim says mean life mu = 10 hours.
- Consumers say it’s less, so we test:
- Null hypothesis H0: mu = 10
- Alternative hypothesis Ha: mu < 10 (one-sided)
2) Use a t-test (because the population standard deviation is unknown and sample size is 24)
- Sample size n = 24
- Sample mean x̄ = 9.4 hours
- Sample standard deviation s = 0.25 hours
- Degrees of freedom = n − 1 = 23
3) Compute the standard error (how much the sample mean typically varies)
- sqrt(24) ≈ 4.899
- standard error = s divided by sqrt(n) = 0.25 / 4.899 ≈ 0.05103
4) Compute the t-statistic
- t = (x̄ − 10) divided by standard error
- That is t = (9.4 − 10) / 0.05103 = −0.6 / 0.05103 ≈ −11.76
5) Decide using t and p-value
- With 23 degrees of freedom, a t of −11.76 is extremely far into the left tail.
- The p-value is basically 0 (much smaller than 0.01).
- Even using a common cutoff like 0.05, this t is way beyond the critical value (about −1.714), so we reject H0.
6) Conclusion in plain teen talk
- The data show the average battery life is significantly less than 10 hours. The manufacturer’s 10-hour claim is not supported by this sample — it’s very likely false.
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