Asked by Ang
please check my answers.
Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the original logarithmic expressions. Give the exact answer.
ln sqrt x+6 = 9 i got {e^9-6}
log (x + 4) = log (5x - 5)
i got: 9/4
log (x + 30) - log 2 = log (3x + 2)
i got: {58}
Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the original logarithmic expressions. Give the exact answer.
ln sqrt x+6 = 9 i got {e^9-6}
log (x + 4) = log (5x - 5)
i got: 9/4
log (x + 30) - log 2 = log (3x + 2)
i got: {58}
Answers
Answered by
drwls
Please limit yourself to one question per post, and show your work
log (x + 4) = log (5x - 5)
As long as the bases of both logs are the same,
x + 4 = 5x - 5
4x = 9
x = 9/4
=======================
log (x + 30) - log 2 = log (3x + 2)
(x+30)/2 = (3x+2)
x + 30 = 6x + 4
5x = 26
x = 5.2
log (x + 4) = log (5x - 5)
As long as the bases of both logs are the same,
x + 4 = 5x - 5
4x = 9
x = 9/4
=======================
log (x + 30) - log 2 = log (3x + 2)
(x+30)/2 = (3x+2)
x + 30 = 6x + 4
5x = 26
x = 5.2
Answered by
bob
true or false, all rational numbers are integers. Explain
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