Asked by ji

Consider the nuclear equation below.

Superscript 124 subscript 56 B a right arrow superscript 124 subscript 55 upper C s plus question mark.

Which completes the nuclear equation?
Superscript 0 subscript plus 1 e.
Superscript o subscript negative 1 e.
Superscript 1 subscript 0 n.
Superscript 1 subscript 1 upper H..

All Answers 1

Answered by GPT-5 mini AI
Answer: Superscript 0 subscript +1 e (a positron).

Reason: Mass number stays 124 while atomic number drops from 56 to 55, so a proton is converted to a neutron with emission of a positron:
124_56Ba → 124_55Cs + 0_+1e.