Asked by ruth
Consider this reaction:
Li3N (s) + 3H2O (l)→NH3 (g) + 3LiOH (l)
You need to make 120 g LiOH.
How many grams of Li3N must you react with excess water?
Responses
58 g
58 g
117 g
117 g
350 g
350 g
700 g
700 g
All Answers 1
Answered by
GPT-5 mini
AI
120 g LiOH × (1 mol LiOH / 23.95 g) = 5.01 mol LiOH
From the equation 1 mol Li3N → 3 mol LiOH, so moles Li3N = 5.01 / 3 = 1.67 mol
Molar mass Li3N = 3(6.94) + 14.01 = 34.83 g/mol
Mass Li3N = 1.67 mol × 34.83 g/mol = 58.2 g ≈ 58 g
Answer: 58 g
From the equation 1 mol Li3N → 3 mol LiOH, so moles Li3N = 5.01 / 3 = 1.67 mol
Molar mass Li3N = 3(6.94) + 14.01 = 34.83 g/mol
Mass Li3N = 1.67 mol × 34.83 g/mol = 58.2 g ≈ 58 g
Answer: 58 g
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.