Question

Ammonia (NH3) can be produced by the reaction of hydrogen gas with nitrogen gas:

3H2 + N2→2NH3

A chemist reacts 2.00 mol H2 with excess N2. The reaction yields 0.13 mol NH3.

What is the percent yield of the reaction?

Responses

10%

10%

40%

40%

60%

60%

80%

80%

Answer 1

Theoretical NH3 from 2.00 mol H2 = 2.00*(2/3) = 1.333... mol.
Percent yield = (0.13 / 1.333...)*100% ≈ 9.75% ≈ 10%.

Answer: 10%.