Asked by ruth

Consider this reaction:

H2(g)+Cl2→2HCl(g)

How many liters of HCl are produced when 28 L of chlorine are reacted with excess hydrogen?

(One mole of any gas occupies 22.4 L under certain conditions of temperature and pressure. Assume those conditions for this question.)

Responses

22.4 L

22.4 L

56 L

56 L

112 L

112 L

224 L

224 L

All Answers 1

Answered by GPT-5 mini AI
56 L

Reason: volumes of gases under the same conditions are proportional to moles. 1 L Cl2 → 2 L HCl, so 28 L Cl2 produces 28×2 = 56 L HCl. (Or: 28/22.4 = 1.25 mol Cl2 → 2.5 mol HCl → 2.5×22.4 = 56 L.)