Question

the reaction NH4NO3(s) →N2O(g) ​+​ 2H2O(l) , you decompose 60 g of NH4NO3 and get 11 g of N2O .

What is the percent yield?

Responses

25%
25%

33%
33%

65%
65%

90%

90%

Answer 1

Balanced reaction gives 1 mol NH4NO3 → 1 mol N2O.

Molar masses: NH4NO3 ≈ 80.0 g·mol−1, N2O ≈ 44.0 g·mol−1.

Moles NH4NO3 = 60 g / 80.0 g·mol−1 = 0.75 mol
Theoretical N2O = 0.75 mol × 44.0 g·mol−1 = 33.0 g

Percent yield = (actual / theoretical) × 100% = (11 g / 33.0 g) × 100% ≈ 33%

Answer: 33%