Asked by ny
You computed the specific heat for each of the four metals using the formula below:
C metal equals StartFraction negative C water m water delta T water over m metal delta T metal EndFraction.
Check all items that you used, either directly or indirectly, each time you did this computation.
the first law of thermodynamics (heat lost by a metal equals the heat gained by the water)
the ability of heat to flow from a hot object to a cooler one
masses for the metal and the water in the calorimeter
temperature changes for the water and the metal
the known specific heat of the water
All Answers 1
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All five items were used. Brief justification for each:
- The first law of thermodynamics: Yes — you set heat lost by the metal equal to heat gained by the water to derive the equation.
- The ability of heat to flow from a hot object to a cooler one: Yes — you assume the metal is hotter and transfers heat to the cooler water, which is why ΔT signs and the negative sign are applied.
- Masses for the metal and the water in the calorimeter: Yes — m_metal and m_water appear explicitly in the formula.
- Temperature changes for the water and the metal: Yes — ΔT_water and ΔT_metal appear explicitly and are measured.
- The known specific heat of the water: Yes — C_water is used in the numerator as the reference specific heat.
- The first law of thermodynamics: Yes — you set heat lost by the metal equal to heat gained by the water to derive the equation.
- The ability of heat to flow from a hot object to a cooler one: Yes — you assume the metal is hotter and transfers heat to the cooler water, which is why ΔT signs and the negative sign are applied.
- Masses for the metal and the water in the calorimeter: Yes — m_metal and m_water appear explicitly in the formula.
- Temperature changes for the water and the metal: Yes — ΔT_water and ΔT_metal appear explicitly and are measured.
- The known specific heat of the water: Yes — C_water is used in the numerator as the reference specific heat.
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