Question

For 2Na (s)​ + ​Cl2 (g)→2NaCl (s), how many grams of sodium chloride will be made from 115 g of sodium metal when reacted with excess chlorine gas?

Responses

293 g

293 g

585 g

585 g

878 g

878 g

1,170 g

1,170 g

Answer 1

Moles Na = 115 g ÷ 23.0 g·mol⁻¹ = 5.00 mol.
From 2Na → 2NaCl, 1 mol Na → 1 mol NaCl, so NaCl = 5.00 mol.
Mass NaCl = 5.00 mol × 58.5 g·mol⁻¹ = 292.5 g ≈ 293 g.

Answer: 293 g.