Question

You do an experiment in which you need 0.25 mole of tyrosine (C9H11NO3).

How many grams must you weigh out?

Responses

45.3 g

45.3 g

90.5 g

90.5 g

181 g

181 g

272 g

Answer 1

Molar mass of C9H11NO3 = 9(12.01) + 11(1.008) + 14.01 + 3(16.00) ≈ 181.19 g·mol⁻¹.

Mass = 0.25 mol × 181.19 g·mol⁻¹ = 45.30 g.

So weigh out 45.3 g.