Question

On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (negative 6, negative 5) and (0, 0). Line J K goes through (negative 6, 1) and (0, negative 4). Line P Q goes through (negative 5, 4) and (0, negative 2).
Which line is perpendicular to a line that has a slope of Negative five-sixths?

line JK
line LM
line NO
line PQ

Answer 1

Line LM.

Slope of LM = (3 − (−3)) / (0 − (−5)) = 6/5, which is the negative reciprocal of −5/6, so LM is perpendicular to a line with slope −5/6.