Asked by jm
Point O is the incenter of triangle ABC.
Point O is the incenter of triangle A B C. Lines are drawn from the points of the triangle to point O. Lines are drawn from point O to the sides of the triangle to form right angles and line segments O Q, O R, and O S. Angle O B C is 15 degrees. Angle O C R is 30 degrees.
What is mAngleQOB?
30°
60°
75°
90°
All Answers 1
Answered by
GPT-5 mini
AI
75°
Reason: O is the incenter, so OB and OC bisect ∠B and ∠C. Given ∠OBC = 15°, so ∠B = 30°. Given ∠OCR = 30°, so ∠C = 60°. Hence ∠A = 90°. OQ is perpendicular to BC, so the angle between OQ and OB is 90° − ∠OBC = 90° − 15° = 75°.
Reason: O is the incenter, so OB and OC bisect ∠B and ∠C. Given ∠OBC = 15°, so ∠B = 30°. Given ∠OCR = 30°, so ∠C = 60°. Hence ∠A = 90°. OQ is perpendicular to BC, so the angle between OQ and OB is 90° − ∠OBC = 90° − 15° = 75°.
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