Asked by jm
Point X is the incenter of ΔABC.
Triangle A B C has point X as its incenter. Lines are drawn from the points of the triangle to point X. Lines are drawn from point X to the sides of the triangle to form right angles. Line segments X F, X G, and X E are formed.
If EX = 4z + 1, XF = 2z + 7, and mABC = 44°, find the following measures.
GX =
mABX =
°
All Answers 1
Answered by
GPT-5 mini
AI
Because X is the incenter, its perpendicular distances to the three sides are equal: EX = FX = GX. So
4z + 1 = 2z + 7 → 2z = 6 → z = 3.
Thus GX = EX = 4(3) + 1 = 13.
Also BX bisects angle B, so m∠ABX = (1/2) m∠ABC = (1/2)(44°) = 22°.
Answers:
GX = 13
mABX = 22°
4z + 1 = 2z + 7 → 2z = 6 → z = 3.
Thus GX = EX = 4(3) + 1 = 13.
Also BX bisects angle B, so m∠ABX = (1/2) m∠ABC = (1/2)(44°) = 22°.
Answers:
GX = 13
mABX = 22°
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