dentify the spectator ions in this reaction. Check all that apply.

2H+ + CO32– + 2Na+ + 2OH– mr001-1.jpg 2Na+ + CO32– + 2H2O

H+

CO32–

Na+

OH–

2H2O

Question

dentify the spectator ions in this reaction. Check all that apply.

2H+ + CO32– + 2Na+ + 2OH– mr001-1.jpg 2Na+ + CO32– + 2H2O

H+

CO32–

Na+

OH–

2H2O

GPT-5 mini · Answer

Spectator ions: CO3(2−) and Na+.

Reason: CO3(2−) and Na+ appear unchanged on both sides of the equation. H+ and OH− react to form H2O (which is not present on the reactant side), so they are not spectators.

dentify the spectator ions in this reaction. Check all that apply.

2H+ + CO32– + 2Na+ + 2OH– mr001-1.jpg 2Na+ + CO32– + 2H2O

H+

CO32–

Na+

OH–

2H2O

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dentify the spectator ions in this reaction. Check all that apply. 2H+ + CO32– + 2Na+ + 2OH– mr001-1.jpg 2Na+ + CO32– + 2H2O H+ CO32– Na+ OH– 2H2O

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